Výpočet limit postupností
Urči nasledujúce limity postupností \( r: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-1}{n+1}\right) \) a \( s: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-9}{n^{2}+3 n}\right) \).
\( r: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-1}{n+1}\right)=1 \quad s: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-9}{n^{2}+3 n}\right)=\infty \)
\( r: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-1}{n+1}\right)=\infty \quad s: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-9}{n^{2}+3 n}\right)=0 \)
\( r: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-1}{n+1}\right)=\infty \quad s: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-9}{n^{2}+3 n}\right)=1 \)
\( r: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-1}{n+1}\right)=0 \quad s: \lim _{n \rightarrow \infty}\left(\frac{n^{2}-9}{n^{2}+3 n}\right)=1 \)