Kořeny komplexní rovnice
Urči v \mathbb{C} kořeny rovnice s komplexními koeficienty:
\large 2\text{i}x^2-\Large \frac{\text{i}\sqrt {2}}{2}\large x+\Large \frac{\sqrt {3}}{16}\large = 0
\large K =\left \{\Large \frac{\sqrt {2}+\sqrt {3}}{8}\large -\Large \frac{1}{8}\large \text{i};\Large \frac{\sqrt {2}-\sqrt {3}}{8}\large +\Large \frac{1}{8}\large \text{i}\right \}
\large K =\left \{\Large \frac{\sqrt {2}-\sqrt {3}}{8}\large +\Large \frac{1}{8}\large \text{i};\Large \frac{\sqrt {2}+\sqrt {3}}{8}\large -\Large \frac{1}{8}\large \text{i}\right \}
\large K =\left \{\Large \frac{\sqrt {2}-\sqrt {3}}{8}\large -\Large \frac{1}{8}\large \text{i};\Large \frac{\sqrt {2}+\sqrt {3}}{8}\large +\Large \frac{1}{8}\large \text{i}\right \}
\large K =\left \{\Large \frac{\sqrt {3}-\sqrt {2}}{8}\large -\Large \frac{1}{8}\large \text{i};\Large \frac{\sqrt {3}+\sqrt {2}}{8}\large +\Large \frac{1}{8}\large \text{i}\right \}