Komplexní číslo v rovnici
Urči v \mathbb{C} komplexní číslo z tak, aby platila rovnice:
\large \Large \frac{\bar{z}+\text{i}^4}{7}\large -4z = 3+2\text{i}
a – bi + 1 – 28(a + bi)=21 + 14i
a+1–28a=21\to a=-\frac{20}{28}
–b–28b=14\to b=–\frac{14}{30}
\large z = -\Large \frac{20}{28}\large -\Large \frac{14}{30}\large \text{i}
a – bi + 1 – 28(a + bi)=21 + 14i
a+1–28a=21\to a=-\frac{20}{27}
–b–28b=14\to b=–\frac{14}{29}
\large z = -\Large \frac{20}{27}\large -\Large \frac{14}{29}\large \text{i}
a – bi + 1 – 28(a + bi)=21 + 14i
a+1–28a=21\to a=-\frac{21}{27}
–b–28b=14\to b=–\frac{15}{29}
\large z = -\Large \frac{21}{27}\large -\Large \frac{15}{29}\large \text{i}
a – bi + 1 – 28(a + bi)=21 + 14i
a+1–28a=21\to a=-\frac{19}{27}
–b–28b=14\to b=–\frac{13}{29}
\large z = -\Large \frac{19}{27}\large -\Large \frac{13}{29}\large \text{i}