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Komplexní číslo v rovnici
Urči v \mathbb{C} komplexní číslo z tak, aby platila rovnice:
\large 6\sqrt {2}\left( \cos {\Large \frac{3\pi}{4}\large }+\text{i}\sin {\Large \frac{3\pi}{4}\large }\right) = \bar{z}-2+6\text{i}
–6=a – 2→a= –5
6= –b + 6→b=1
\large z =-5
–6=a – 2→a= –3
6= –b + 6→b=2
\large z =-3
–6=a – 2→a= –6
6= –b + 6→b=3
\large z =-6
–6=a – 2→a= –4
6= –b + 6→b=0
\large z =-4