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Riešenie trigonometrickej rovnice
Rieš v ℝ rovnicu:
\( \normalsize-sin^2x+2cosx+2=0 \)
\( cos\ x = 0 \)
\( cos\ x = 1 \)
\( \normalsize K=\bigcup\limits_{k\in\mathbb{Z}}\left\{2k\pi\right\} \)
\( cos\ x = r \)
\( cos\ x = −1 \)
\( \normalsize K=\bigcup\limits_{k\in\mathbb{Z}}\left\{\pi+2k\pi\right\} \)
\( cos\ x = \frac{3}{2} \)
\( cos\ x = -\frac{1}{2} \)
\( \normalsize K=\bigcup\limits_{k\in\mathbb{Z}}\left\{\frac{2\pi}{3}+2k\pi\right\} \)
\( cos\ x = \frac{1}{2} \)
\( cos\ x = 0 \)
\( \normalsize K=\bigcup\limits_{k\in\mathbb{Z}}\left\{\frac{\pi}{3}+2k\pi\right\} \)