0 %
Komplexní číslo v rovnici
Urči v \mathbb{C} komplexní číslo z tak, aby platila rovnice:
\large 11^2+\text{i}^3-4\text{i}^6\left( 2+\Large \frac{\text{i}}{2}\large \right) = 2+\Large \frac{z}{4}\large
11^2–i+4(2+\frac{i}{2})=2+\frac{z}{4}
121–i+8+2i=2+\frac{z}{4}
484 – 4i + 32 + 8i=8 + z
508 + 4i=z
\large z = 508-4\text{i}
11^2–i+4(2+\frac{i}{2})=2+\frac{z}{4}
121–i+8+2i=2+\frac{z}{4}
484 – 4i + 32 + 8i=8 + z
508 + 4i=z
\large z = 508+8\text{i}
11^2–i+4(2+\frac{i}{2})=2+\frac{z}{4}
121–i+8+2i=2+\frac{z}{4}
484 – 4i + 32 + 8i=8 + z
508 + 4i=z
\large z = 504+4\text{i}
11^2–i+4(2+\frac{i}{2})=2+\frac{z}{4}
121–i+8+2i=2+\frac{z}{4}
484 – 4i + 32 + 8i=8 + z
508 + 4i=z
\large z = 508+4\text{i}