Uhly pravidelného 15-uholníka
Aké veľké budú jednotlivé uhly daného pravidelného n-uholníka?
\( \normalsize n=15 \)
\( \large\alpha=\frac{\left(n-2\right)\cdot180\degree}{n}=\frac{\left(15-3\right)\cdot180\degree}{15}=\frac{12\cdot180\degree}{15}=\frac{2160\degree}{15}=144\degree \)
\( \large\alpha=\frac{\left(n-2\right)\cdot180\degree}{n}=\frac{\left(15-2\right)\cdot180\degree}{15}=\frac{13\cdot180\degree}{15}=\frac{2340\degree}{15}=156\degree \)
\( \large\alpha=\frac{\left(n-2\right)\cdot180\degree}{n}=\frac{\left(15-2\right)\cdot180\degree}{14}=\frac{13\cdot180\degree}{14}=\frac{2340\degree}{14}=167.14\degree \)
\( \large\alpha=\frac{\left(n-3\right)\cdot180\degree}{n}=\frac{\left(15-2\right)\cdot180\degree}{15}=\frac{13\cdot180\degree}{15}=\frac{2340\degree}{15}=154\degree \)