Tasso di completamento
0 %
Řešení trigonometrické rovnice
Řeš v \( \R \) rovnici:
\( \large -sin^{2}x + 2cosx + 2 = 0 \)
\( cos\ x = 0 \)
\( cos\ x = 1 \)
\( K = \bigcup_\limits{k\ \in\ \mathbb{Z}} \left \{2k\pi \right\} \)
\( cos\ x = \frac{\sqrt{2}}{2} \)
\( cos\ x = \frac{-\sqrt{2}}{2} \)
\( K = \bigcup_\limits{k\ \in\ \mathbb{Z}} \left \{\frac{\pi}{4} + 2k\pi \right\} \)
\( cos\ x = \frac{1}{2} \)
\( cos\ x = 0 \)
\( K = \bigcup_\limits{k\ \in\ \mathbb{Z}} \left \{\frac{\pi}{3} + 2k\pi \right\} \)
\( cos\ x = r \)
\( cos\ x = −1 \)
\( K = \bigcup_\limits{k\ \in\ \mathbb{Z}} \left \{\pi + 2k\pi \right\} \)