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Uprava podmienok v zlomku
Uprav v \( \R \) urč podmienky:
\( \large\frac{{2x+y}}{{x^2+xy}}-\frac{1}{x} \)
\( \large=\frac{2x+y-x-y}{x\cdot\left(x+y\right)}=\frac{x}{x\cdot\left(x+y\right)}= \)
\( \large=\frac{1}{x+y} \)
\( \normalsize x\neq0;x\neq-y \)
\( \large=\frac{2x+y-x-y}{x\cdot\left(x+y\right)}=\frac{x}{x\cdot\left(x+y\right)}= \)
\( \large=\frac{1}{x-y} \)
\( \normalsize x\neq0;x\neq-y \)
\( \large=\frac{2x+y-x-y}{x\cdot\left(x+y\right)}=\frac{x}{x\cdot\left(x+y\right)}= \)
\( \large=\frac{1}{x} \)
\( \normalsize x\neq0;x\neq-y \)
\( \large=\frac{2x+y-x-y}{x\cdot\left(x+y\right)}=\frac{x}{x\cdot\left(x+y\right)}= \)
\( \large=\frac{1}{x+y+1} \)
\( \normalsize x\neq0;x\neq-y \)