Úprava zlomku
Uprav v \( \R \) a urč podmienky:
\( \large\frac{{x^3+y^3}}{{x^2-y^2}} \)
\( \large\frac{x^3+y^3}{x^2-y^2}=\frac{\left(x-y\right)\cdot\left(x^2+xy+y^2\right)}{\left(x+y\right)\cdot\left(x-y\right)}= \)
\( \large=\frac{x^2+xy+y^2}{x+y} \)
\( \normalsize x\neq\pm y \)
\( \large\frac{x^3+y^3}{x^2-y^2}=\frac{\left(x+y\right)\cdot\left(x^2-xy+y^2\right)}{\left(x+y\right)\cdot\left(x+y\right)}= \)
\( \large=\frac{x^2-xy+y^2}{x+y} \)
\( \normalsize x\neq\pm y \)
\( \large\frac{x^3+y^3}{x^2-y^2}=\frac{\left(x+y\right)\cdot\left(x^2-xy+y^2\right)}{\left(x-y\right)\cdot\left(x+y\right)}= \)
\( \large=\frac{x^2-xy+y^2}{x+y} \)
\( \normalsize x\neq\pm y \)
\( \large\frac{x^3+y^3}{x^2-y^2}=\frac{\left(x+y\right)\cdot\left(x^2-xy+y^2\right)}{\left(x+y\right)\cdot\left(x-y\right)}= \)
\( \large=\frac{x^2-xy+y^2}{x-y} \)
\( \normalsize x\neq\pm y \)