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Výpočet obsahu plochy pod křivkou
Urči obsah plochy pod křivkou funkce na daném intervalu:
\( \large h\left( x\right) = x^{-2},\text{na intervalu}\left \langle-3;-1 \right \rangle \)
\( \large=-\left(-1\right)^{-1}-\left[-\left(-3\right)^{-1}\right]=1-\left[-\Large\frac{1}{3}\right]=\Large\frac{4}{3}\large j^2 \)
\( \large=-\left(-1\right)^{-1}-\left[-\left(-3\right)^{-1}\right]=1-\left[-\Large\frac{1}{-3}\right]=\Large\frac{1}{3}\large j^2 \)
\( \large=-\left(-1\right)^{-1}-\left[-\left(-3\right)^{-1}\right]=1-\left[-\Large\frac{1}{-3}\right]=\Large\frac{5}{3}\large j^2 \)
\( \large=-\left(-1\right)^{-1}-\left[-\left(-3\right)^{-1}\right]=1-\left[-\Large\frac{1}{-3}\right]=\Large\frac{2}{3}\large j^2 \)