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Řešení rovnice s absolutními hodnotami
Řeš v \( \R \) rovnici:
\( \large \left | {x + 2} \right | = 4\left | {x-3} \right | \)
\( \large K = K_{1}\mathop\cup K_{2}\mathop\cup K_{3} = \left \{ {3;\Large \frac{{14}}{3}\large } \right \} \)
\( \large K = K_{1}\mathop\cup K_{2}\mathop\cup K_{3} = \left \{ {1;\Large \frac{{14}}{3}\large } \right \} \)
\( \large K = K_{1}\mathop\cup K_{2}\mathop\cup K_{3} = \left \{ {2;\Large \frac{{14}}{3}\large } \right \} \)
\( \large K = K_{1}\mathop\cup K_{2}\mathop\cup K_{3} = \left \{ {2;\Large \frac{{16}}{3}\large } \right \} \)