0 %
Racionalizácia zlomku
Uprav v \( \R \) a urč podmienky:
\( \large\frac{{x^2-4}}{{x^2-x-6}} \)
\( \large\frac{x^2-4}{x^2-x-6}=\frac{\left(x+2\right)\cdot\left(x-2\right)}{\left(x+2\right)\cdot\left(x+3\right)}=\frac{x-2}{x+3} \)
\( \normalsize x\neq3,x\neq-2 \)
\( \large\frac{x^2-4}{x^2-x-6}=\frac{\left(x+2\right)\cdot\left(x-2\right)}{\left(x+2\right)\cdot\left(x-3\right)}=\frac{x-2}{x-3} \)
\( \normalsize x\neq3,x\neq-2 \)
\( \large\frac{x^2-4}{x^2-x-6}=\frac{\left(x+2\right)\cdot\left(x-2\right)}{\left(x-1\right)\cdot\left(x-3\right)}=\frac{x-2}{x-1} \)
\( \normalsize x\neq3,x\neq-2 \)
\( \large\frac{x^2-4}{x^2-x-6}=\frac{\left(x+2\right)\cdot\left(x-2\right)}{\left(x-2\right)\cdot\left(x-3\right)}=\frac{x+2}{x-3} \)
\( \normalsize x\neq3,x\neq-2 \)