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Limit of Sequence
Urč limitu postupnosti \( \normalsize a_{n}=\frac{n+2}{n^2+3} \).
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{n+2}{n^2+3}\right)=0} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{n+2}{n^2+3}\right)=\frac{1}{2}} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{n+2}{n^2+3}\right)=1} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{n+2}{n^2+3}\right)=\infty} \)