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Převod komplexního čísla
Vypočítej a převeď komplexní číslo z^{5}=\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5} na algebraický tvar.
z^{5}=\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5}=32\left(\cos \frac{5 \pi}{6}+i \sin \frac{5 \pi}{6}\right)=-32 \sqrt{3}+16 i
z^{5}=\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5}=32\left(\cos \frac{5 \pi}{6}+i \sin \frac{5 \pi}{6}\right)=-16 \sqrt{3}-16 i
z^{5}=\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5}=32\left(\cos \frac{5 \pi}{6}+i \sin \frac{5 \pi}{6}\right)=-16 \sqrt{3}+16 i
z^{5}=\left[2\left(\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}\right)\right]^{5}=32\left(\cos \frac{5 \pi}{6}+i \sin \frac{5 \pi}{6}\right)=16 \sqrt{3}+16 i