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Riešenie nerovnice so štvorcovými koreňmi
Rieš v \( \R \) nerovnicu:
\( \normalsize\sqrt{x+1}+\sqrt{x-2}\ge\sqrt{2-x} \)
\( \sqrt{x+1}+\sqrt{x-2}\geq\sqrt{2-x} \)
\( \sqrt{4+1}+\sqrt{4-2}\geq\sqrt{2-4} \)
\( \sqrt{5}\geq\sqrt{-2} \)
\( \normalsize K=\left\{4\right\} \)
\( \sqrt{x+1}+\sqrt{x-2}\geq\sqrt{2-x} \)
\( \sqrt{2+1}+\sqrt{2-2}\geq\sqrt{2-2} \)
\( \sqrt{3}\geq0 \)
\( \normalsize K=\left\{2\right\} \)
\( \sqrt{x+1}+\sqrt{x-2}\geq\sqrt{2-x} \)
\( \sqrt{0+1}+\sqrt{0-2}\geq\sqrt{2-0} \)
\( \sqrt{1}\geq2 \)
\( \normalsize K=\left\{0\right\} \)
\( \sqrt{x+1}+\sqrt{x-2}\geq\sqrt{2-x} \)
\( \sqrt{1+1}+\sqrt{1-2}\geq\sqrt{2-1} \)
\( \sqrt{2}\geq1 \)
\( \normalsize K=\left\{1\right\} \)