Úprava lomeného výrazu v reálných číslech
Uprav v \mathbb{R} lomený výraz a urči podmínky:
\large 1-\Large \frac{1}{{2+\frac{1}{{3-\frac{1}{z}}}}}\large
= \frac{{7{z}\ –\ 2\ –\ 3{z}\ + 1}}{{7{z}\ – 2}} =
= \frac{{4{z}\ – 1}}{{7{z}\ – 2}}
\large {z} \neq \Large \frac{1}{3}\large ,{z} \neq \Large \frac{2}{7}\large ,{z} \neq 0
= \frac{{7{z}\ –\ 2\ –\ 3{z}\ + 1}}{{7{z}\ – 2}} =
= \frac{{4{z}\ – 1}}{{7{z}\ + 2}}
\large {z} \neq \Large \frac{1}{3}\large ,{z} \neq \Large \frac{2}{7}\large ,{z} \neq 0
= \frac{{7{z}\ –\ 2\ –\ 3{z}\ + 1}}{{7{z}\ – 2}} =
= \frac{{4{z}\ + 1}}{{7{z}\ – 2}}
\large {z} \neq \Large \frac{1}{3}\large ,{z} \neq \Large \frac{2}{7}\large ,{z} \neq 0
= \frac{{7{z}\ –\ 2\ –\ 3{z}\ + 1}}{{7{z}\ – 2}} =
= \frac{{4{z}\ – 1}}{{7{z}\ – 2}}
\large {z} \neq \Large \frac{1}{3}\large ,{z} \neq \Large \frac{2}{7}\large ,{z} \neq 1