Rieš v dané množine lineárnou rovnicu:
\( \large2\left(x+3\right)-3\left(\frac14x+2\right)=\frac{x+11}{8} \) v intervale \( \left(-3;\:1\rangle\right. \)
\( \normalsize K=\{0\} \)
\( \normalsize K=\{1\} \)
\( \normalsize K=\emptyset \)
\( \normalsize K=\{-1\} \)