Vypočítání argumentu logaritmu
Vypočítej argument \( x \) z logaritmu:
\( \large {\log _9}x = - \Large \frac{1}{2}\large \)
\( \frac{1}{9^\frac{1}{3}} = x \)
\( \frac{1}{\sqrt[3]{9}} = x \)
\( x = \frac{1}{2} \)
\( \frac{1}{9^2} = x \)
\( \frac{1}{81} = x \)
\( x = \frac{1}{81} \)
\( \frac{1}{9^\frac{1}{2}} = x \)
\( \frac{1}{\sqrt{9}} = x \)
\( x = \frac{1}{3} \)
\( \frac{1}{9^\frac{1}{4}} = x \)
\( \frac{1}{\sqrt[4]{9}} = x \)
\( x = \frac{1}{\sqrt[4]{9}} \)