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Řešení nerovnice
Vypočítej v \( \mathbb{R} \):
\( \sqrt{6 x-x^{2}}>2 x \)
\( K=\left(-1 ; \frac{6}{5}\right) \)
\( K=\left(1 ; \frac{6}{5}\right) \)
\( K=\left(0 ; \frac{6}{5}\right) \)
\( K=\left(0 ; \frac{5}{6}\right) \)
Vypočítej v \( \mathbb{R} \):
\( \sqrt{6 x-x^{2}}>2 x \)
\( K=\left(-1 ; \frac{6}{5}\right) \)
\( K=\left(1 ; \frac{6}{5}\right) \)
\( K=\left(0 ; \frac{6}{5}\right) \)
\( K=\left(0 ; \frac{5}{6}\right) \)