Podmínky pro úpravu výrazu
Uprav a napiš podmínky:
\large \Large \frac{{{{\left( {a-\frac{1}{a}} \right) }^{- 2}}+{{\left( {a+\frac{1}{a}} \right) }^{- 2}}}}{{{{\left( {a-\frac{1}{a}} \right) }^{- 2}}-{{\left( {a+\frac{1}{a}} \right) }^{- 2}}}}\large
=\frac{2\left (a^{2}\ +\ \frac{1}{a^{2}} \right )}{4} = \frac{\frac{a^{4}\ +\ 1}{a^{2}}}{2}= \frac{a^{4}\ +\ 2}{2a^{2}}
\large a\neq 0, a\neq \pm 1
=\frac{2\left (a^{2}\ +\ \frac{1}{a^{2}} \right )}{4} = \frac{\frac{a^{4}\ +\ 1}{a^{2}}}{2}= \frac{a^{4}\ +\ 1}{4a^{2}}
\large a\neq 0, a\neq \pm 1
=\frac{2\left (a^{2}\ +\ \frac{1}{a^{2}} \right )}{4} = \frac{\frac{a^{4}\ +\ 1}{a^{2}}}{2}= \frac{a^{4}\ +\ 1}{2a^{2}}
\large a\neq 0, a\neq \pm 1
=\frac{2\left (a^{2}\ +\ \frac{1}{a^{2}} \right )}{4} = \frac{\frac{a^{4}\ +\ 1}{a^{2}}}{2}= \frac{a^{4}\ -\ 1}{2a^{2}}
\large a\neq 0, a\neq \pm 1