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Limit of a Sequence
Urč limitu postupnosti
\( \normalsize{\displaystyle\lim_{n\to\infty}\frac{3n^3-4n^2+1}{n^4+5n}} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{3n^3-4n^2+1}{n^4+5n}\right)=1} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{3n^3-4n^2+1}{n^4+5n}\right)=-1} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{3n^3-4n^2+1}{n^4+5n}\right)=0} \)
\( \normalsize{\displaystyle\lim_{n\to\infty}\left(\frac{3n^3-4n^2+1}{n^4+5n}\right)=\infty} \)