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Rovnica s absolútnou hodnotou
Rieš v \( \R \) rovnicu:
\( \normalsize\left|{x^2+2x}\right|-\left|{2-x}\right|=\left|{x^2-x}\right| \)
\( \large K=K_1\mathop{\cup}K_2\mathop{\cup}K_3\mathop{\cup}K_4\mathop{\cup}K_5=\left\{{\frac{{\sqrt3-1}}{2}}\right\} \)
\( \large K=K_1\mathop{\cup}K_2\mathop{\cup}K_3\mathop{\cup}K_4\mathop{\cup}K_5=\left\{{\frac{{\sqrt5+1}}{2}}\right\} \)
\( \large K=K_1\mathop{\cup}K_2\mathop{\cup}K_3\mathop{\cup}K_4\mathop{\cup}K_5=\left\{{\frac{{\sqrt5-1}}{2}}\right\} \)
\( \large K=K_1\mathop{\cup}K_2\mathop{\cup}K_3\mathop{\cup}K_4=\left\{{\frac{{\sqrt5-1}}{2}}\right\} \)