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Výpočet obsahu plochy pod křivkou
Urči obsah plochy pod křivkou funkce na daném intervalu:
\( \large g\left( x\right) = \sin {x},\text{na intervalu}\left \langle 0;\pi \right \rangle \)
\( \large=-\cos{\pi}-\left(-\cos{0}\right)=-\left(-1\right)-\left(-1\right)=2j^2 \)
\( \large=-\cos{\pi}-\left(-\cos{0}\right)=-\left(-1\right)-\left(-1\right)=1j^2 \)
\( \large=-\cos{\pi}-\left(-\cos{0}\right)=-\left(1\right)-\left(-1\right)=0j^2 \)
\( \large=-\cos{\pi}-\left(-\cos{0}\right)=-\left(-1\right)-\left(1\right)=0j^2 \)