Usměrnění zlomků
Usměrni zlomky:
\large \Large \frac{5}{{ \sqrt [ 3] {3}+2}}\large
\large = \Large \frac{{5 \left( { 4-2\sqrt [ 3] {3}+\sqrt [ 3] {9}} \right) }}{{11}}\large
\large = \Large \frac{{5 \left( { 4+2\sqrt [ 3] {3}-\sqrt [ 3] {9}} \right) }}{{11}}\large
\large = \Large \frac{{5 \left( { 4-2\sqrt [ 3] {3}+\sqrt [ 3] {9}} \right) }}{{13}}\large
\large = \Large \frac{{5 \left( { 4-2\sqrt [ 3] {3}-\sqrt [ 3] {9}} \right) }}{{11}}\large
Tentokrát se budeš zabývat třetí odmocninou, která je ještě navíc v součtu s číslem dva. Potřebuješ ve jmenovateli získat vzorec (a + b) · (a2 – ab + b2) = a3 + b3, jenž tě zbaví třetí odmocniny.
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