Procentuální složení propantriolu
Určete procentuální složení následující sloučeniny:
propantriolu
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{3\cdot M_{r}(\mathrm{C})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{36,03}{92,03}=0,3915\Rightarrow\bm{39,15}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{8\cdot M_{r}(\mathrm{H})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{8}{92,03}=0,0869\Rightarrow\bm{8,69}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{4\cdot M_{r}(\mathrm{O})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{64}{92,03}=0,6951\Rightarrow\bm{69,51}\%\mathbf{O}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{3\cdot M_{r}(\mathrm{C})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{36,03}{92,03}=0,3915\Rightarrow\bm{39,15}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{6\cdot M_{r}(\mathrm{H})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{6}{92,03}=0,0652\Rightarrow\bm{6,52}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{5\cdot M_{r}(\mathrm{O})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{80}{92,03}=0,8693\Rightarrow\bm{86,93}\%\mathbf{O}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{2\cdot M_{r}(\mathrm{C})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{24,02}{92,03}=0,2609\Rightarrow\bm{26,09}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{10\cdot M_{r}(\mathrm{H})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{10}{92,03}=0,1087\Rightarrow\bm{10,87}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{3\cdot M_{r}(\mathrm{O})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{48}{92,03}=0,5216\Rightarrow\bm{52,16}\%\mathbf{O}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{3\cdot M_{r}(\mathrm{C})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{36,03}{92,03}=0,3915\Rightarrow\bm{39,15}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{8\cdot M_{r}(\mathrm{H})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{8}{92,03}=0,0869\Rightarrow\bm{8,69}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{C}_3\mathrm{H}_5(\mathrm{OH})_3\right)=\frac{3\cdot M_{r}(\mathrm{O})}{M_{r}\left(C_3H_5(\mathrm{OH})_3\right)}=\frac{48}{92,03}=0,5216\Rightarrow\bm{52,16}\%\mathbf{O}\end{array} \)