Výpočet procentuálního obsahu solí v hydrátu
Určete procentuální obsah solí v jejím hydrátu:
\( \left(\mathrm{CH}_3\mathrm{COO}\right)_2\mathrm{Pb}\:v\:\left(\mathrm{CH}_3\mathrm{COO}\right)_2\mathrm{~Pb}\cdot3\mathrm{H}_2\mathrm{O} \)
\( f\left(\left(CH_3COO\right)_2~Pb\cdot3H_2O=\frac{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb}\right)}{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \cdot3 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{325,24}{379,24}=0,8576\Rightarrow\bm{88,76\%}\left(\mathbf{CH}_3\mathbf{COO}\right)_2\mathbf{Pb}\right. \)
\( f\left(\left(CH_3COO\right)_2~Pb\cdot3H_2O=\frac{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb}\right)}{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \cdot3 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{325,24}{379,24}=0,8576\Rightarrow\bm{87,76\%}\left(\mathbf{CH}_3\mathbf{COO}\right)_2\mathbf{Pb}\right. \)
\( \mathrm{f}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \cdot 3 \mathrm{H}_{2} \mathrm{O}=\frac{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb}\right)}{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \cdot 3 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{325,24}{379,24}=0,8576 \Rightarrow \mathbf{8 5 , 7 6 \%}\left(\mathbf{C H}_{3} \mathbf{C O O}\right)_{2} \mathbf{P b}\right. \)
\( f\left(\left(CH_3COO\right)_2~Pb\cdot3H_2O=\frac{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb}\right)}{M_{r}\left(\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{~Pb} \cdot3 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{325,24}{379,24}=0,8576\Rightarrow\bm{86,76\%}\left(\mathbf{CH}_3\mathbf{COO}\right)_2\mathbf{Pb}\right. \)