Výpočet procentuálního složení acetylenu
Určete procentuální složení následující sloučeniny:
acetylenu
\( \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=\frac{2 \cdot M_{r}(C)}{M_{r}\left(C_{\left.2 H_{2}\right)}\right.}=\frac{24,02}{28,02}=0,8571 \Rightarrow \mathbf{8 5 , 7 1} \% \mathrm{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-85,71 \%=\mathbf{1 4 , 2 9 \%} \mathbf{H} \)
\( \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=\frac{2 \cdot M_{r}(C)}{M_{r}\left(C_{\left.2 H_{2}\right)}\right.}=\frac{24,02}{30,02}=0,8000 \Rightarrow \mathbf{8 0 , 0 0} \% \mathrm{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-80,00 \%=\mathbf{2 0 , 0 0 \%} \mathbf{H} \)
\( \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=\frac{2 \cdot M_{r}(C)}{M_{r}\left(C_{\left.2 H_{2}\right)}\right.}=\frac{24,02}{26,02}=0,9231 \Rightarrow \mathbf{9 2 , 3 1} \% \mathrm{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-92,31 \%=\mathbf{7 , 6 9 \%} \mathbf{H} \)
\( \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=\frac{2 \cdot M_{r}(C)}{M_{r}\left(C_{\left.2 H_{2}\right)}\right.}=\frac{24,02}{32,02}=0,7506 \Rightarrow \mathbf{7 5 , 0 6} \% \mathrm{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-75,06 \%=\mathbf{2 4 , 9 4 \%} \mathbf{H} \)