Procentuální složení octanu sodného
Určete procentuální složení následující sloučeniny:
octanu sodného
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(C)}{M_{r}\left(CH_3\mathrm{COONa}\right)}=\frac{24,02}{82,02}=0,2929\Rightarrow\bm{29,29}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{3\cdot M_{r}(H)}{M_{r}\left(\mathrm{H}_3\mathrm{COONa}\right)}=\frac{3}{82,02}=0,0366\Rightarrow\bm{3,66}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(O)}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{32}{82,02}=0,3901\Rightarrow\bm{39,01}\%\mathbf{O}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{M_{r}(\mathrm{Na})}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{24}{82,02}=0,2926\Rightarrow\bm{29,26}\%\bm{~Na}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(C)}{M_{r}\left(CH_3\mathrm{COONa}\right)}=\frac{24,02}{82,02}=0,2929\Rightarrow\bm{29,29}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{3\cdot M_{r}(H)}{M_{r}\left(\mathrm{H}_3\mathrm{COONa}\right)}=\frac{3}{82,02}=0,0366\Rightarrow\bm{3,66}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(O)}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{32}{82,02}=0,3901\Rightarrow\bm{39,01}\%\mathbf{O}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{M_{r}(\mathrm{Na})}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{21}{82,02}=0,2561\Rightarrow\bm{25,61}\%\bm{~Na}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(C)}{M_{r}\left(CH_3\mathrm{COONa}\right)}=\frac{24,02}{82,02}=0,2929\Rightarrow\bm{29,29}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{3\cdot M_{r}(H)}{M_{r}\left(\mathrm{H}_3\mathrm{COONa}\right)}=\frac{3}{82,02}=0,0366\Rightarrow\bm{3,66}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(O)}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{32}{82,02}=0,3901\Rightarrow\bm{39,01}\%\mathbf{O}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{M_{r}(\mathrm{Na})}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{23}{82,02}=0,2804\Rightarrow\bm{28,04}\%\bm{~Na}\end{array} \)
\( \large\begin{array}{l}\mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(C)}{M_{r}\left(CH_3\mathrm{COONa}\right)}=\frac{24,02}{82,02}=0,2929\Rightarrow\bm{29,29}\%\mathbf{C}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{3\cdot M_{r}(H)}{M_{r}\left(\mathrm{H}_3\mathrm{COONa}\right)}=\frac{3}{82,02}=0,0366\Rightarrow\bm{3,66}\%\mathbf{H}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{2\cdot M_{r}(O)}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{32}{82,02}=0,3901\Rightarrow\bm{39,01}\%\mathbf{O}\\ \mathrm{f}\left(\mathrm{CH}_3\mathrm{COONa}\right)=\frac{M_{r}(\mathrm{Na})}{M_{r}\left(\mathrm{CH}_3\mathrm{COONa}\right)}=\frac{22}{82,02}=0,2683\Rightarrow\bm{26,83}\%\bm{~Na}\end{array} \)