Procentuální zastoupení dusíku v oxidu dusíku
Určete procentuální zastoupení dusíku v oxidu dusíku:
\( \mathrm{N}_{2} \mathrm{O}_{5} \)
\( \mathrm{f}\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)=\frac{2 \cdot M_{r}(N)}{M_{r}\left(N_{2} O_{5}\right)}=\frac{28}{108}=0,2593 \Rightarrow \mathbf{2 6}, \mathbf{9 3} \% \mathbf{N} \)
\( \mathrm{f}\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)=\frac{2 \cdot M_{r}(N)}{M_{r}\left(N_{2} O_{5}\right)}=\frac{28}{108}=0,2593 \Rightarrow \mathbf{2 5}, \mathbf{9 3} \% \mathbf{N} \)
\( \mathrm{f}\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)=\frac{2 \cdot M_{r}(N)}{M_{r}\left(N_{2} O_{5}\right)}=\frac{28}{108}=0,2593 \Rightarrow \mathbf{2 5}, \mathbf{8 3} \% \mathbf{N} \)
\( \mathrm{f}\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)=\frac{2 \cdot M_{r}(N)}{M_{r}\left(N_{2} O_{5}\right)}=\frac{28}{108}=0,2593 \Rightarrow \mathbf{2 4}, \mathbf{9 3} \% \mathbf{N} \)