Procento krystalové vody v dekahydrátu síranu sodného
Kolik procenta krystalové vody obsahuje:
dekahydrát síranu sodného
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{8 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{144}{322,06}=0,4471=>\mathbf{44,71} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{10 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{180}{322,06}=0,5589=>\mathbf{55,89} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{9 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{162}{322,06}=0,5025=>\mathbf{50,25} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{11 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{198}{322,06}=0,6150=>\mathbf{61,50} \% \mathbf{H}_{2} \mathbf{O} \)