Procento krystalové vody v dekahydrátu uhličitanu sodného
Kolik procenta krystalové vody obsahuje:
dekahydrát uhličitanu sodného
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{9 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{162}{286,01}=0,5664=>\mathbf{5 6 , 6 4} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{10 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 9 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{180}{268,01}=0,6716=>\mathbf{6 7 , 1 6} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{10 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{180}{286,01}=0,6293=>\mathbf{6 2 , 9 3} \% \mathbf{H}_{2} \mathbf{O} \)
\( \mathrm{f}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)=\frac{11 \cdot M_{r}\left(\mathrm{H}_{2} \mathrm{O}\right)}{M_{r}\left(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right)}=\frac{198}{286,01}=0,6923=>\mathbf{6 9 , 2 3} \% \mathbf{H}_{2} \mathbf{O} \)