Procentuální složení benzenu
Určete procentuální složení následující sloučeniny:
benzenu
\( \mathrm{f}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{6 \cdot M_{r}(C)}{M_{r}\left(C_{6} H_{6}\right)}=\frac{72,06}{78,06}=0,9231=>\mathbf{9 2 , 3 1} \% \mathbf{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-92,31 \%=\mathbf{7 , 6 9 \%} \mathbf{~ H} \)
\( \mathrm{f}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{6 \cdot M_{r}(C)}{M_{r}\left(C_{6} H_{6}\right)}=\frac{72,06}{78,06}=0,9231=>\mathbf{9 2 , 3 1} \% \mathbf{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-92,31 \%=\mathbf{6 , 6 9 \%} \mathbf{~ H} \)
\( \mathrm{f}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{6 \cdot M_{r}(C)}{M_{r}\left(C_{6} H_{6}\right)}=\frac{72,06}{78,06}=0,9231=>\mathbf{9 2 , 3 1} \% \mathbf{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-92,31 \%=\mathbf{8 , 6 9 \%} \mathbf{~ H} \)
\( \mathrm{f}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)=\frac{6 \cdot M_{r}(C)}{M_{r}\left(C_{6} H_{6}\right)}=\frac{72,06}{78,06}=0,9231=>\mathbf{9 2 , 3 1} \% \mathbf{C} \quad \mathrm{f}\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)=100 \%-92,31 \%=\mathbf{5 , 6 9 \%} \mathbf{~ H} \)