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Kořeny komplexní rovnice
Urči v \mathbb{C} kořeny rovnice \mathrm{i} \sqrt{3} x^{2}+x-\frac{1}{4}=0.
K=\left\{\frac{\sqrt{6}}{12}-\frac{2 \sqrt{3}-3 \sqrt{2}}{12} \mathrm{i} ;-\frac{\sqrt{3}}{12}+\frac{2 \sqrt{3}+3 \sqrt{2}}{12} \mathrm{i}\right\}
K=\left\{\frac{\sqrt{6}}{12}-\frac{2 \sqrt{3}-3 \sqrt{2}}{12} \mathrm{i} ;-\frac{\sqrt{3}}{12}-\frac{2 \sqrt{3}+3 \sqrt{2}}{12} \mathrm{i}\right\}
K=\left\{\frac{\sqrt{6}}{12}-\frac{2 \sqrt{3}+3 \sqrt{2}}{12} \mathrm{i} ;-\frac{\sqrt{3}}{12}+\frac{2 \sqrt{3}-3 \sqrt{2}}{12} \mathrm{i}\right\}
K=\left\{\frac{\sqrt{6}}{12}+\frac{2 \sqrt{3}-3 \sqrt{2}}{12} \mathrm{i} ;-\frac{\sqrt{3}}{12}-\frac{2 \sqrt{3}+3 \sqrt{2}}{12} \mathrm{i}\right\}